Heat loss through single glass pane.xls
Description
KNOWN: Inner and outer surface temperatures of a glass window of prescribed dimensions.
FIND: Heat loss through window.
ASSUMPTIONS: 1. Onedimensional conduction in the x direction
2. Steady state conditions
3. Constant properties
Calculation Reference
Fundamentals of Heat and Mass Transfer  Frank P. Incropera
To calculate the heat loss through a single glass pane, considering the inner and outer surface temperatures of the glass window and the given assumptions, you can follow these steps:

Determine the surface area of the glass pane: Calculate the surface area of the glass pane, which is the area of one side of the pane.

Calculate the temperature difference: The temperature difference (ΔT) across the glass pane is given by:
ΔT = T_inner  T_outer
Where T_inner is the inner surface temperature and T_outer is the outer surface temperature.

Calculate the thermal conductivity: The thermal conductivity (k) of the glass material is a property specific to the glass type being used.

Calculate the thickness: The thickness (L) of the glass pane can be measured or obtained from specifications.

Calculate the heat flux: The heat flux (q') through the glass pane is given by Fourier's Law of heat conduction:
q' = (k * ΔT) / L
Where k is the thermal conductivity and L is the thickness of the glass pane.

Calculate the heat loss: The heat loss (Q) through the glass pane is obtained by multiplying the heat flux by the surface area:
Q = q' * Surface Area
By following these steps, you can determine the heat loss through a single glass pane based on the given inner and outer surface temperatures, and the assumptions of onedimensional conduction in the x direction, steadystate conditions, and constant properties.
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